Java program to find year is a leap year or not | infoStud blogs

This post is about how to write a java program or code for finding out the year is a leap year or not. Leap year is a year in which February has only 28 days in a month and it comes after a gap of every 4 years.

 
For writing a java program t find out the year is a leap year or not required basic concepts of conditional statements especially concepts related to the "if-else". Let's begin to write code.

Test Condition

Input the year: 2008

2008 is a leap year

Objective: 

Write a Java program that takes a year from the user and prints whether that year is a leap year or not. 

Code

import java.util.Scanner;

public class LeapYearOrNot {

  

  public static void main(String[] args)

    {

        Scanner in = new Scanner(System.in);

        System.out.print("Input the year: ");

        int year = in.nextInt();

        boolean x = (year % 4) == 0;

        boolean y = (year % 100) != 0;

        boolean z = ((year % 100 == 0) && (year % 400 == 0));

        if (x && (y || z))

        {

            System.out.println(year + " is a leap year");

        }

        else

        {

            System.out.println(year + " is not a leap year");

        }

    }

}

Output

Input the year: 2008

2008 is a leap year